Y=120-4x+x^2

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Solution for Y=120-4x+x^2 equation: 



=120-4Y+Y^2

We move all terms to the left:

-(120-4Y+Y^2)=0

We get rid of parentheses

-Y^2+4Y-120=0

We add all the numbers together, and all the variables

-1Y^2+4Y-120=0

a = -1; b = 4; c = -120;
Δ = b2-4ac
Δ = 42-4·(-1)·(-120)
Δ = -464
Delta is less than zero, so there is no solution for the equation

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